Question

PLESE solve this 20 points for free​

Answer 1

Answer:

p(x) = x3 - 3x2 -2x + 6.

x =

$p{x} \: = \sqrt{2 } \\ \\ px = ( \sqrt{2) }3 - 3( \sqrt{2) {}^{2} } - 2( \sqrt{2) } + 6 \\ \\ = 2 \sqrt{2} - 3(2) - 2 \sqrt{2} - 6$

$2 \sqrt{2 } - 2 \sqrt{2} + 6 - 6 = 0$

Answer 2

Answer:

p(x) = x3 - 3x2 -2x + 6.

x:

p(x)=√2

p(x)=(√2)³-3(√2)²-2√2+6

p(x)=2√2-3*2-2√2+6

p(x)=2√2-2√2-6+6

p(x)=0