Question

Plese solve this

quadratic equation ​

Answer 1

Step-by-step explanation:

x/3+3/6-x=2(6+x)/15

3/6-x=12+2x/15-x/3

3/6-x=12+2x-5x/15

3/6-x=12-3x/15

45=6(12-3x)-x(12-3x)

45=72-18x12x+3x²

45=3x²-30x+72

3x²-30x+27=03x²-27x-3x+27=0

3x(x-9)-3(x-9)=0

(3x-3) (x-9)=0

x=3/3=1 or x=9

Answer 2

Answer:

x = 9,1

Step-by-step explanation:

x + 3 = 2(6+x)

3 6-x 15

→ (6-x) + 9 = 2(6+x)

3(6-x) 15

→ 6x-x² + 9 = 6(6+)x(6-x)

15

→ 5(6-x²+9) = 2(36-x²)

→ 30x-5x²+45 = 72-2x²

→ -3x²+30x-27 = 0

→ 3(-x²+10x-9) = 0

→ -x²+10x-9 = 0

→ x²-10x+9 = 0

→ x²-x-9x+9 = 0

→ x(x-1)-9(x-1) = 0

→ (x-9)(x-1) = 0

→ x = 9,1