Question

Plese solve this

x²-5x+6=0​

Answer 1

Step-by-step explanation:

${x}^{2} - 5x + 6 = 0 \\ {x}^{2} - 2x - 3x + 6 = 0 \\ x < x - 2 > - 3 < x - 2 > = 0 \\ note \: \: here < > is \: used \: for \: bracket. \\ < x - 3 > < x - 2 > \\ so \: value \: of \: x \: are \: 3 \: and\: 2.$

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Answer 2

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