pleses answer it fast its very very urgent.
Attachments:
Answers
Answered by
0
First, we have to find the mid values of the data.
class interval mid value(x) frequencies(f) fx
0-10 (0+10)/2 = 5 8 8*5 = 40
10-20 (10+20)/2 = 15 16 16*15 = 240
20-30 (20+30)/2 = 25 36 36*25 = 900
30-40 (30+40)/2 = 35 34 34*35 = 1190
40-50 (40+50)/2 = 45 6 6*45 = 270
Total: 125 100 2640
Mean = sum of fx/sum of f
= 2640/100 = 26.4 is mean
Number of terms = 100
Since 100 is even
Median = n/2 = 100/2 = 50
Class interval Frequency Cummaltaive frequency
0-10 8 8
10-20 16 24
20-30 36 60
30-40 34 94
40-50 6 100
So median is 29 or 30 since 50 lies in between 20-30
Modulas class is 20-30 since frequency is more.
Mode is also 29
class interval mid value(x) frequencies(f) fx
0-10 (0+10)/2 = 5 8 8*5 = 40
10-20 (10+20)/2 = 15 16 16*15 = 240
20-30 (20+30)/2 = 25 36 36*25 = 900
30-40 (30+40)/2 = 35 34 34*35 = 1190
40-50 (40+50)/2 = 45 6 6*45 = 270
Total: 125 100 2640
Mean = sum of fx/sum of f
= 2640/100 = 26.4 is mean
Number of terms = 100
Since 100 is even
Median = n/2 = 100/2 = 50
Class interval Frequency Cummaltaive frequency
0-10 8 8
10-20 16 24
20-30 36 60
30-40 34 94
40-50 6 100
So median is 29 or 30 since 50 lies in between 20-30
Modulas class is 20-30 since frequency is more.
Mode is also 29
Similar questions