Question

pless solve this........

Answer 1

$let \: \alpha \: and \: \beta \: be \: the \: zeroes \: of \: the \: polynomial$

Then,

$\alpha + \beta = (\alpha \beta) \div 2$

We also know,

$\alpha + \beta = - b \div a \\ \alpha \beta = c \div a$

So,

→ -b/a = (c/a)/2 = (c/2a)

→ -2b = c ______(i)

and from the given equation:

a = 3, b = 2k+1 ,& c= -(k-5)

Putting values of a, b, & c in equation (i), we get:

→ -2(2k + 1) = -(k-5)

→ -4k - 2 = -k + 5

→ 3k = 3

→ k = 1

Thankyou!!!

Answer 2

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