Question

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Answer 1

When the resistance is doubled up

it gets connected in parallel combination

So by applying parallel combination theory :-

The new resistance will be derived as

==>

1/6 + 1/6 = 1/R

==>

R = 3 ohm

Answer 2

Explanation:

we know that

R = rho(p) x length / area

R = p x l / A -- eqn 1

wire is doubled so area will be doubled means 2A and length will be halved means l/2

New resistance = p x (l/ 2) / 2A

New resistance = ( p x l )/4 A

from eqn 1 we get,

new resistance = R / 4

Rnew = R/4 = 6/ 4 = 1.5 ohm

therefore new resistance of wire is 1.5 ohm

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