plez answer me!!!! This is a linear equation
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let his monthly salary = x
and annual increment = y
then after 2 year
x+2y = 11000 .............(1)
again after 4 year
x+4y=14000 ..................(2)
applying (2) -(1) we get
x+4y-(x+2y)=14000-11000=3000
2y = 3000
y = 1500
by equation (1) x= 11000-2y =11000 -3000 =8000
monthly salary is 8000 and annual increment is 1500 . ans
and annual increment = y
then after 2 year
x+2y = 11000 .............(1)
again after 4 year
x+4y=14000 ..................(2)
applying (2) -(1) we get
x+4y-(x+2y)=14000-11000=3000
2y = 3000
y = 1500
by equation (1) x= 11000-2y =11000 -3000 =8000
monthly salary is 8000 and annual increment is 1500 . ans
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