Question

plez answer this compound interest question

Answer 1

Answer:

1 वर्ष

Step-by-step explanation:

P = मूल = ₹ 12000

r = ब्याज दर = 10 % वार्षिक

संयोजन प्रति छह महीने => n = 2 ( एक  वर्ष में दो बार )

चक्रवृद्धि ब्याज = ₹ 1230

A = मूल + चक्रवृद्धि ब्याज  = 12000 + 1230 = ₹ 13230

t = ?  वर्ष

$A = P\times(1 + \frac{r}{100n})^{nt}$

$\implies13230 = 12000\times(1 + \frac{10}{200})^{2t}\\\\\implies 1323 = 1200\times(1.05)^{2t}\\\\\implies \frac{1323}{1200} = (1.05)^{2t}\\\\\implies \frac{441}{400} = (1.05)^{2t}\\\\\implies \frac{21^2}{20^2} = (1.05)^{2t}\\\\\implies (\frac{21}{20})^2 = (1.05)^{2t}\\\\\implies (1.05)^2 = (1.05)^{2t}\\\\\implies 2 = 2t\\\\\implies t = 1$

समय = 1 वर्ष