Math, asked by Anonymous, 3 months ago

plez Answer this question........
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Answers

Answered by priyadpriyadarshini3

1

Answer:

ANSWER

dx

dy

=0

dθ

dy

=d

2

3

(sin2θ)

dθ

dy

=d

4

3

(cos2θ) ---- (1)

dθ

dy

=e

θ

sinθ+e

θ

cosθ ---- (2)

dy

dx

=

4

3

e

θ

(sin θ+cos θ)

cos2θ

=0

cos2θ=0

2θ=π/2

θ=π/4

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