plez Answer this question........
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dx
dy
=0
dθ
dy
=d
2
3
(sin2θ)
dθ
dy
=d
4
3
(cos2θ) ---- (1)
dθ
dy
=e
θ
sinθ+e
θ
cosθ ---- (2)
dy
dx
=
4
3
e
θ
(sin θ+cos θ)
cos2θ
=0
cos2θ=0
2θ=π/2
θ=π/4
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