plezz can anyone give me solution of it
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put 2x²=t
then 4x=dt/dx
xdx=1/4dt
£1/4√(1+t)dt
1/4(1+t)^3/2)/(3/2)+c
(1×2)/(4×3)[1+2x²]^³/2+c
1/6(1+2x²)^3/2+c
then 4x=dt/dx
xdx=1/4dt
£1/4√(1+t)dt
1/4(1+t)^3/2)/(3/2)+c
(1×2)/(4×3)[1+2x²]^³/2+c
1/6(1+2x²)^3/2+c
Answered by
1
Here is your answer........
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