Question

plezzzz ans this question

Answer 1

Hi dear here is your solution...

15tan^2 x +4(tan^2 x+1)=23

= 19tan^2 x +4 = 23

= 19tan^2 x = 19

= tan^2 x =1

= tanx= 1

therefore

secx=root2

cosecx=root2

sinx=1/root2

(secx+cosecx)^2-sin^2 x =(2root2)^2-1/2=8-1/2=15/2

If you got mark as brainiest

Answer 2

Here is your answer:-

15tan^2 x +4(tan^2 x+1)=23

= 19tan^2 x +4 = 23

= 19tan^2 x = 19

= tan^2 x =1

= tanx= 1

therefore

secx=root2

cosecx=root2

sinx=1/root2

(secx+cosecx)^2-sin^2 x =(2root2)^2-1/2=8-1/2=15/2

Mark it as brainliest answer....