Math, asked by helper90, 11 months ago

pliz solve this question.......

Attachments:

Answers

Answered by Grimmjow
4

\textsf{Let the Number of Flowers in the Basket of Radha at the Beginning be : F}

\sf{Let\;the\;First\;Temple\;be\;denoted\;by : T_1}

\sf{Let\;the\;Second\;Temple\;be\;denoted\;by : T_2}

\sf{Let\;the\;Third\;Temple\;be\;denoted\;by : T_3}

\textsf{Given : At each temple, She offers one half of the Flowers from the Basket}

\sf{\implies Flowers\;offered\;at\;Temple\;T_1 = \dfrac{F}{2}}

\sf{Remaining\;Flowers\;in\;the\;Basket\;after\;offering\;at\;Temple\;T_1 = \big(F - \dfrac{F}{2}\big) = \dfrac{F}{2}}

\sf{Now,\;Radha\;visits\;Temple\;T_2 :}

\sf{\implies Flowers\;offered\;at\;Temple\;T_2 = \dfrac{\dfrac{F}{2}}{2} = \dfrac{F}{4}}

\sf{Remaining\;Flowers\;in\;the\;Basket\;after\;offering\;at\;Temple\;T_2 = \big(\dfrac{F}{2} - \dfrac{F}{4} \big) = \dfrac{F}{4}}

\sf{Now,\;Radha\;visits\;Temple\;T_3 :}

\sf{\implies Flowers\;offered\;at\;Temple\;T_3 = \dfrac{\dfrac{F}{4}}{2} = \dfrac{F}{8}}

\sf{Remaining\;Flowers\;in\;the\;Basket\;after\;offering\;at\;Temple\;T_3 = \big(\dfrac{F}{4} - \dfrac{F}{8} \big) = \dfrac{F}{8}}

\sf{Given : After\;offering\;at\;Temple\;T_3,\;Radha\;is\;remained\;with\;3\;Flowers}

\sf{We\;found\;that,\;Remaining\;Flowers\;in\;the\;Basket\;after\;offering\;at\;Temple T_3 = \dfrac{F}{8}}

\sf{\implies \dfrac{F}{8} = 3}

\sf{\implies F = 24}

\sf{\implies Number\;of\;Flowers\;Radha\;had\;in\;the\;Beginning = 24}

\sf{\implies Number\;of\;Flowers\;Radha\;offered\;at\;Temple\;T_1 = \dfrac{F}{2} = \dfrac{24}{2} = 12}

\sf{\implies Number\;of\;Flowers\;Radha\;offered\;at\;Temple\;T_2 = \dfrac{F}{4} = \dfrac{24}{4} = 6}

\sf{\implies Number\;of\;Flowers\;Radha\;offered\;at\;Temple\;T_3 = \dfrac{F}{8} = \dfrac{24}{8} = 3}


helper90: thanks
Answered by pratyush4211
2
Let Radha Have=X flowers

She Visited 3 temples
And Give 1/2 of flowers

At First Temple=1/2×x=x/2 flowers(Remain=x/2)
At second Temple=x/2×1/2=x/4 (Remain=x/4)
At Third Temple=x/4×1/2=x/8 flowers

So In All temple She use flowers
=X/2+x/4+x/8
=4x+2x+x/8. (LCM=8)
=7x/8

She Use Flower=7x/8
But Remain=3 flowers

MEANS Total Flower-Use flower=3
A/Q
x -  \frac{7x}{8}  = 3 \\  =  \frac{8x - 7x}{8}  = 3 \\  \frac{x}{8}  = 3 \\ x = 8 \times 3 \\ x = 24
Total Flowers➡️24

At 1st temple=24/2=12 flowers
At 2nd Temple=24/4=6 flowers
At Third Temple=24/8=3 flowers

Remain=3
Total➡️24 Flowers
Similar questions