Question

plizz solve this question
name of the chapter is complex number​

Answer 1

Answer:

+ b uska answer hoga smjhe

Answer 2

Step-by-step explanation:

iv. {

$( { {i}^{17} - (\frac{1}{i}) }^{34}) ^{2}$

=

$( {i}^{16 + 1} - ({i})^{32 + 2})^{2}$

as

$\frac{1}{i } = \frac{1 \times i}{i \times i} = - i$

and

${ - i}^{34} = {i}^{34} = {i}^{32 + 2}$

Now, we have

$= (i - ( - 1))^{2}$

as, we know,

${i}^{4n + 1} = i$

and,

${i}^{4n + 2} = ( - 1)$

,where, i belongs to real number