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Given : ∠A + ∠B = 125° , ∠A + ∠C = 113°
To find : ∠A , ∠B , ∠C
Solution:
∠A + ∠B = 125°
∠A + ∠C = 113°
Adding both
∠A + ∠B + ∠A + ∠C = 125° + 113°
=> ∠A + ( ∠A + ∠B + ∠C ) = 238°
Sum of angles of a triangle = 180°
=> ∠A + 180° = 238°
=> ∠A = 58°
∠A + ∠B = 125° => 58° + ∠B = 125° => ∠B = 67°
∠A + ∠C = 113° => 58° + ∠C = 113° => ∠C = 55°
∠A = 58° , ∠B = 67° , ∠C = 55°
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