Question

pllz give me answer plz​

Answer 1

Answer:

Explanation:

The reaction of HCl and CaCO3 is:

2HCl + CaCO3 → CaCl2 + CO2 + H2O

So, for every mole of CaCO3, 2 moles of HCl will be required. If you have 50 g of limestone then that is, approximately, 50 g of CaCO3. The molecular weight of CaCO3 is about 106 g/mol. So, the number of moles of CaCO3 in 50 g is:

(50 g)/(106 g/mol) = 0.472 mol

And you need twice as much HCl so you will need

2 * 0.472 mol = 0.943 mol

to ‘decompose’ 50 g of limestone.