Math, asked by kediaronit2005, 10 months ago

pllzzz simplify all the three points by rationalizing rhe denominator.....
whoevwr will correctly answer the que will be marked brainliest by mee...
but check ur answer before posting​

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Answers

Answered by kamleshkantaria
1

Answer:

Step-by-step explanation:

(i) Multiply both the numerator and the denominator of the number with   the conjugate of the denominator(7 - 3 root5)

The conjugate of the denominator 7 - 3 root5 is 7 + 3 root5

That is,

= 7 + 3 root5/7 - 3 root5 X 7 + 3 root5/7 + 3 root5

Now,

Follow the identity

= 7^2 + 2(7)(3 root5) + (3 root5)^2[using identity (a + b)^2 = a^2 + 2ab + b^2]/7^2 - (3 root5)^2[using identity a^2 - b^2 = (a + b)(a - b)]

= 49 + 48 root5 + 45/49 - 45

= 49 + 45 + 48 root5/4

= 94 + 42 root5/4

= 47 + 21 root5/2

(ii) Multiply both the numerator and the denominator of the number with   the conjugate of the denominator(2 root2 + 3 root3)

The conjugate of the denominator 2 root2 + 3 root3 is 2 root2 - 3 root3

That is,

= 2 root3 - root5/2 root2 + 3 root3 X 2 root2 - 3 root3/2 root2 - 3 root3

Now,

Follow the identity

= (2 root3 + root5)(2 root2 - 3 root3)/(2 root2)^2 - (3 root3)^2[using  identity a^2 - b^2 = (a + b)(a - b)]

= 2 root 3 X 2 root2 - 2 root3 X 3 root3 + root5 X 2 root2 - root5 X 3 root3[using distributive property of multiplication]/4 X 2 - 9 X 3

= 4 root6 - 6 root9 + 2 root10 - 3 root15/8 - 27

= 4 root6 - 6 X 3(3^2 = 9) + 2 root10 - 3 root15/-19

= 4 root6 -18 + 2 root10 - 3 root15/-19

Make the denominator's sign positive

= - (4 root6 -18 + 2 root10 - 3 root15)/19

= - 4 root6 + 18 - 2 root10 + 3 root15/19

(iii) Multiply both the numerator and the denominator of the number with   the conjugate of the denominator(root48 + root18)

The conjugate of the denominator root48 + root18 is root48 - root18

That is,

= 7 root3 - 5 root2/root48 + root18 X root48 - root18/root48 - root18

Now,

Follow the identity

= (7 root3 - 5 root2)(root48 - root18)/(root48)^2 - (root18)^2[using  identity a^2 - b^2 = (a + b)(a - b)]

= 7 root3 X root48 - 7 root3 X root18 - 5 root2 X root48 + 5 root2 X root18[using distributive property of multiplication]/48(root48^2 = 48) - 18(root18^2 = 18)

= 7 root144 - 7 root54 - 5 root96 + 5 root36/30

= 7 X 12(12^2 = 144) + 5 X 6(6^2 = 36) - 7 root54 - 5 root96/30

= 84 + 30 - 7 root54 - 5 root96/30

= 114 - 7 root54 + 5 root96/30

Answered by amitnrw
1

Given :   (7 + 3√5) / ( 7 - 3√5) ,   (2√3  -  √5)/(2√2 + 3√3)

To find :  rationalizing the denominator.....

Solution:

(7 + 3√5) / ( 7 - 3√5)

multiplying numerator & denominator by 7 + 3√5

= (7 + 3√5) (7 + 3√5)  / (7 - 3√5) (7 + 3√5)

= ( 49 + 45 + 42√5)/(49 - 45)

= (94 +  42√5)/(4)

= (47 + 21√5)/2

(2√3  -  √5)/(2√2 + 3√3)

multiplying numerator & denominator by  3√3 - 2√2

(2√3  -  √5) ( 3√3 - 2√2) / (2√2 + 3√3) ( 3√3 - 2√2)

= ( 18 + 2√10 - 4√6 - 3√15)/(27  - 8)

= ( 18 + 2√10 - 4√6 - 3√15)/19

Learn More:

simplify 6-4√3|/6+4√3 by rationalizing the denominator

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