plot (2,3) (6,7) (9,8) or graph and find area of triangle so formed
Answers
Plot the points in a rough diagram and take them in order.
Let the vertices be A(1,2),B(−3,4) and C(−5,−6)
Now the area of △ABC is
=
2
1
{(x
1
y
2
+x
2
y
3
+x
3
y
1
)−(x
2
y
1
+x
3
y
2
+x
1
y
3
)}
=
2
1
{(4+18−10)−(−6−20−6)}
=
2
1
(12+32)=22 sq.units.
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Given :-
- Coordinates 1 (x1, y1) = (2, 3)
- Coordinates 2 (x2, y2) = (6, 7)
- Coordinates 3 (x3, y3) = (9, 8)
To Find :-
- Find what is the area of triangle so formed ?
Formula used :-
- Area = |(1/2)[x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)]|
Solution :- (For rough diagram, refer to image.)
Putting all values we get,
→ Area = |(1/2)[2(7 - 8) + 6(8 - 3) + 9(3 - 7)]|
→ Area = (1/2)[2(-1) + 6(5) + 9(-4)]|
→ Area = |(1/2)(-2 + 30 - 36)|
→ Area = |(1/2)(-8)|
→ Area = |(-4)|
→ Area = 4 unit². (Ans.)
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