Question

plot 3x+y=1 please can do on graph ​

Answer 1

First, solve for two points which solve the equation and plot these points:

First Point: For

x

=

0

(

3

⋅

0

)

−

y

=

1

0

−

y

=

1

−

y

=

1

−

1

×

−

y

=

−

1

×

1

y

=

−

1

or

(

0

,

−

1

)

Second Point: For

y

=

2

3

x

−

2

=

1

3

x

−

2

+

2

=

1

+

2

3

x

−

0

=

3

3

x

=

3

3

x

3

=

3

3

x

=

1

or

(

1

,

2

)

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+1)^2-0.04)((x-1)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x - y - 1)(x^2+(y+1)^2-0.04)((x-1)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}