Question

plot a(5 3) b(-2 3) and d(5 -4) are the vertices of square ABCD . Plot these points an a graph paper and hence find the coordinate of vertex C

plz give correct ans

Answer 1

Answer:

Let ABCD be the quadrilateral plot.

Produce BA to meet CD drawn parallel to CA at E.

Join EC.

Triangles EAC and ADC lie on the same line and between same parallels DE and CA.

Using the property mentioned above

ar(EAC)=ar(ADC)

ar(ABCD)=ar(ABC)+ar(ACD)

=ar(ABC)+ar(ADC)

=ar(ABC)+ar(EAC)=ar(EBC)

i.e.,

Quadrilateral ABCD=△EBC gives the explanation .

Step-by-step explanation:

Let ABCD be the quadrilateral plot.

Produce BA to meet CD drawn parallel to CA at E.

Join EC.

Triangles EAC and ADC lie on the same line and between same parallels DE and CA.

Using the property mentioned above

ar(EAC)=ar(ADC)

ar(ABCD)=ar(ABC)+ar(ACD)

=ar(ABC)+ar(ADC)

=ar(ABC)+ar(EAC)=ar(EBC)

i.e.,

Quadrilateral ABCD=△EBC gives the explanation .