Question

Plot a graph showing variation of de broglie wavelength associated with a charged particle of mass m versus 1/√v ,where v is the potential difference through which the particle is accelerated .how does this graph give us the information regarding the magnitude of the charge of the particle?

Answer 1

Answer:

The graph of de-broglie wavelength and 1/√v is a straight line and the slope of the graph will help us to calculate the value of the charge

Explanation:

As we know that the charge is accelerated through a fixed potential difference V

So here kinetic energy of the charge is

$K = qV$

now by the relation of momentum and kinetic energy we have

$K = \frac{p^2}{2m}$

so we have

$p = \sqrt{2mK}$

now we know that de Broglie wavelength of the particle is given as

$\lambda = \frac{h}{P}$

so we have

$\lambda = \frac{h}{\sqrt{2mK}}$

$\lambda = \frac{h}{\sqrt{2mqV}}$

so here we can say that wavelength is inversely proportional to the square root of voltage V

so the graph between de-broglie wavelength and 1/√v must be a straight line

Slope of the graph is given as

$m = \frac{h}{\sqrt{2mq}}$

so we can find the charge of the particle with the help of the slope of the graph

#Learn

Topic : De-Broglie wavelength

https://brainly.in/question/14391290