:Plot the following coordinate points on a plane.
a.A(2,3) b.M(4,0)
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Answers
Answer:
A = x = 2
y = 3
in 1st cood......
&
M = x = 4
y = 0
on line x .
point on 4 in positive.
ok
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Step-by-step explanation:
Answer:
Given :-
Mass of object = 100 kg
Initial velocity = 5 m/s
Final velocity = 8 m/s
Time taken = 6 sec
To Find :-
Mounmentum
Magnitude
Force exerted
Solution :-
As we know that
\huge \tt \: P = mvP=mv
Here,
P denotes Mounmentum
M denotes Mass
V denotes Velocity
Firstly let's calculate initial Mounmentum
\huge \fbox{PI = mu}
PI = mu
Here,
PI = Initial Mounmentum
M = Mass
U = Initial Mounmentum
\tt \: PI = 100 \times 5PI=100×5
\tt \: PI = 500 \: mpsPI=500mps
Now,
Let's find final Mounmentum
As we know that
\huge \fbox{PF = mv}
PF = mv
Here,
PF = Final Mounmentum
M = Mass
V = Final Mounmentum
\tt \: PF = 100 \times 8PF=100×8
\tt \: PF = 800 \: mpsPF=800mps
Now,
Let's find Acceleration
\huge \boxed{ \bf \: A = \dfrac{v - u}{t}}
A=
t
v−u
Here,
A = Acceleration
V = Final Mounmentum
U = Initial Mounmentum
T = Time
\tt \: A = \dfrac{8 - 5}{6}A=
6
8−5
\tt \: A = \dfrac{3}{6}A=
6
3
\tt \: A = \dfrac{1}{2} \: = 0.5 \: mpsA=
2
1
=0.5mps
Now,
Let's find force exerted
\huge \fbox{F = ma}
F = ma
Here,
F = Force
M = Mass
A = Acceleration
\tt \: F = 100 \times 0.5F=100×0.5
\tt \: F = 50 \: NF=50N