Question

Plot the following points in the coordinate plane; A (-5, -2), B (1, -2), C (6, 4), D (0, 4). Join the points to get AB, BC, CD, and DA. Name the figure formed so obtained.
pls don't give useless answer

Answer 1

Answer:

Step-by-step explanation:

AB║CD , AB lies on the line y = - 2 and CD lies on the line y = 4 ; AB = CD = 6.

$Slope_{BC}$ = (4 - (- 2)) / (6 - 1) = 6/5

$Slope_{AD}$ = (-2 - 4) / (-5 - 0) = 6/5

AD = √[(-5-0)² + (-2-4)²] = √(25 + 36) = √61

BC = √[(1-6)² + (-2-4)²] = √(25 + 36) = √61

AD║BC and AD = BC.

Thus, ABCD is a parallelogram.