Plot the graph for 2(x+3) - 3 ( y+1 ) = 0 and. find 1) Quadrant in which the line segment intercepted between the axis line ? 2) Shade the triangular region and write the vertices of triangle
Answers
Given : 2(x+3) - 3 ( y+1 ) = 0
To Find : Plot the graph
1. Write the quadrant in which the line segment intercepted between the axes lie.
2. Shade the triangle region formal by the line and the axes.
3. Write the vertices of the triangle so formed.
Solution:
2(x+3) - 3 ( y+1 ) = 0
=> 2x – 3y + 3 = 0
x = 0 => y = 1
x = 3 => y = 3
x = - 3 => y = - 1
y = 0 => x = - 3/2
plot the line passing through the points
the quadrant in which the line segment intercepted between the axes line.
2nd Quadrant
Shaded the triangle region formal by the line and the axes.
vertices of the triangle so formed.
(0,0) , ( -3/2 , 0) , ( 0 , 1)
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