Plot the point P (3,0), Q (7,9) R (6,9) and S (-2,0)
Name the figure PQRS ?
Find the area of PQRS?
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Given: The points P (3,0), Q (7,9) R (6,9) and S (-2,0)
To find: Name the figure PQRS ? Find the area of PQRS?
Solution:
- Now we have given the points P (3,0), Q (7,9) R (6,9) and S (-2,0) .
- After plotting on graph it comes out to be a quadrilateral with no specific shape.
- Now let A be (7,0) and B be (-2,9).
- Now ASBQ forms rectangle
area of ASBQ = 9 X 9 = 81 cm^2
- Now we will subtract area of triangle SBR and PAQ for area of rectangle.
area of SBR = 1/2 X 8 X 9 = 36 cm^2
area of PAQ = 1/2 X 4 X 9 = 18 cm^2
- Now:
area of PQRS = area of ASBQ - ( area of SBR + area of PAQ )
area of PQRS = 81 - (36 + 18)
area of PQRS = 81 - (54)
area of PQRS =27 cm^2
Answer:
So the area of PQRS is 27 cm^2.
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