Question

Plot the points (3, 2), (- 2, 2), (- 2, - 2) and (3, - 2) in the Cartesian plane. Join these po in order and name the figure so formed.

Answer 1

$\large\underline{\sf{Solution-}}$

Given coordinates are ( 3, 2 ), ( - 2, 2 ), ( - 2, - 2 ) and ( 3, - 2 ).

Let assume that

↝ Coordinates of A be (3, 2)

↝ Coordinates of B (- 2, 2)

↝ Coordinates of C (- 2, - 2)

↝ Coordinates of D (3, - 2).

[ Please see the attachment ].

From graph we concluded that

↝ AB = 5 units

↝ BC = 4 units

↝ CD = 5 units

↝ DA = 4 units

Also,

↝ AB is Perpendicular to BC.

↝ BC is perpendicular to CD

↝ CD is perpendicular to DA

↝ DA is perpendicular to AB.

It implies, AB = CD = 5 units and BC = DA = 4 units.

As we know that,

In a quadrilateral, if opposite sides are equal and angle between the sides is 90°, then quadrilateral is a rectangle.

So, this figure, ABCD is a rectangle.

Hence,

Coordinates ( 3, 2 ), ( - 2, 2 ), ( - 2, - 2 ) and ( 3, - 2 ) are the vertices of triangle.