Question

plot the points A(1,1),B(-1,5),C(7,9) and D(9,5) name the type of figure ABCD.In which Quadrant the point of Intersect of diagonal i,e.

Answer 1

As per question :- Coordinate are A(1,1) , B(-1,5), C(7,9) , D(9,5)

with these coordinates the equations of the lines formed are -

Equation of AB - y= -2x + 3
Equation of BC - 2y= x + 11
Equation of CD - y= -2x + 23
Equation of AD - 2y = X + 1

From the above equations we can deduce that lines AB and BC are perpendicular , lines CD and AD are perpendicular, lines AB and CD are parallel, lines BC and AD are parallel. Thus the quadrilateral formed from the coordinates ABCD is rectangular.
So, it's a rectangle.

Now, the mid point or intersection point of the diagonals is - (4,5) which lies in the first quadrant.