Question

Plot the points A
(-2,3) B(-2,0), C(2,0) and D(2,6) on the graph paper. Join them consecutively. Find the lengths of AC and AD

Answer 1

$\bold{\boxed{Hoi!}}$☺️

$\textbf{Refer the attachment for graph section}$

•$\bold{\underline{Finding AC and AD}}$

By Distance formula we have,

AC²= (-2-2)²+ (3-0)² = 16+9 = 25
=> AC = $\sqrt{25}$
=> AC = 5 units.

Similarly,

AD²= (-2-2)²+(3-6)²= 16+9 = 25
=> AD = $\sqrt{25}$
=> AD = 5 units.

$\bold{\underline{Thanks!}}$☺️☺️

Answer 2

Answer:

$AC = 5units\\AD = 5units$

Step-by-step explanation:

According to the question,

We have,

A(-2,3), B(-2,0), C(2,0), and D(2,6).

As we know,

Distance formula

$d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}$

$d = distance\\(x_1, y_1) = coordinates of the first point\\(x_2, y_2) = coordinates of the second point$

By the Distance formula,

let's find the length of the AC-

$AC^2= (-2-2)^2+(3-0)^2\\\\AC^2 = 16+9 = 25\\\\AC = \sqrt{25} \\\\AC = 5 units.$

Similarly,

let's find the length of AC

$AD^2= (-2-2)^2+(3-6)^2\\\\AD^2 = 16+9 = 25\\\\AD = \sqrt{25} \\\\AD = 5 units.$