Question

plot the points A(-5,3 ),B(3,3 ), C(3,0) ,D(-5,0) in the Cartesian plane. name the figure ABCD and find the ratios of areas of two parts of ABCD in the 1 qradrant and the 2 quadrant ​

Answer 1

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Answer 2

CONCEPT:

If we plot this in a cartesian plane it will be become two parts.

The total quadrilateral will be divided into two  rectangles by the axis.

so we want to just find the area of the rectangle using the distance between the cordinates and  compare the ratio.

GIVEN:

the points are given.

A(-5,3 ),

B(3,3 ),

C(3,0) ,

D(-5,0) .

The method is also given.

Find the two rectangles and then compare ratio of areas.

FIND:

compare the ratio of  area of two rectangles.

SOLUTION:

The rectangle at left side have coordinates A(-5,3 ), D(-5,0) and (0,3) and (0,0)

$\left[\begin{array}{ccc}-5,3&0,3\\-5,0&0,0\end{array}\right]$

so the area of the rectangle is 3*5=15

the square at right side have  coordinates B(3,3), C(3,0) and  (0,3) and (0,0)

so the area of square is 3*3=9.

so the ratio  rectangle in first quadrant: rectangle in first quadrant is 15:9=5:3.

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