Question

Plot three points A(4, 0), B(0, -4) and C(-4, 0) on the coordinates plane. Now,plot point D so that ABCD is a rhombus. Give coordinates of the D.

Answer 1

Answer:

A will be plotted on X axis

B will be plotted on -Y axis

C will be plotted on -X axis

And

The coordinates of D will be (0,4) and will be plotted on Y axis.

Answer 2

$\Large{\underline{\underline{\bold{Given:}}}}$

• ABCD is a Rhombus.
• Point A = (4,0)
• Point B = (0,4)
• Point C = (-4,0)

$\Large{\underline{\underline{\red{\bold{➸To\;Find:}}}}}$

• Co-ordinated of Point D.

$\Large{\underline{\underline{\blue{\bold{✄Solution:}}}}}$

$\boxed{\green{\sf{Midpoint = \frac{X_1+X_2}{2},\frac{Y_1+Y_2}{2}}}}$

WKT

Diagonals of Rhombus intersect at a point. So, midpoint of the diagonals is same.

The diagonals are AC and BD

AC:-

$\frac{(4 + ( - 4))}{2} , \frac{(0 + 0)}{2} \\ \frac{0}{2} , \frac{0}{2} \\ (0,0)$

BD:-

Let, The Point D be $\sf{(X_4,Y_4)}$

$\pink{\sf{Refer\;The\; Attachment.}}$

• Co-ordinates of D ☞ $\Large\red{\bold{(0,4)}}$

$\boxed{\tt{@MrSovereign}}$

Hope This Helps!!