Plot two points A(5,0) and B(-5,0) on the graph paper. Now plot C unique or there can be more than one point C so that ∆ ABC is isosceles
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Lets find out the length of AB.
B is represented as (3,4) and A as (5,0)
Distance AB = √(3-5)² + (4-0) = √20
Lets find out the length of AC.
C is represented as (7,4) and A as (5,0)
Distance AC = √(7-5)² + (4-0) = √20
Hence proved that we do have an isosceles triangle.
B is represented as (3,4) and A as (5,0)
Distance AB = √(3-5)² + (4-0) = √20
Lets find out the length of AC.
C is represented as (7,4) and A as (5,0)
Distance AC = √(7-5)² + (4-0) = √20
Hence proved that we do have an isosceles triangle.
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