Question

PLOTT
The present age of the father is 4 years more than thrice the age of his son Three years later father's age will be 10 years more than twice the age of his son.
What is the present age of father in years​

Answer 1

Answer:

let the present age of son be x and father be 3x+4

so,

3x+4+3= 2(x+3) +10

therefore, 3x+7=2x+6+10 , so, x= 16-7 , hence, x=9

therefore present age of son=9 years and that of father=3×9+4 =27+4=31 years

Answer 2

Answer:

Father's present age is 31 years .

Step-by-step explanation:

Explanation:

Given , the present age of the father is 4 years more than thrice the age of his son .

Let the present age of son be x years .

Than , present age of father = 3x + 4

Step 1:

Three years later , age of son = x + 3

And age of father = 3x+4 +3= 3x+ 7 ......(i)

According, to the question three years later father's age will be 10 years more than twice to the age of his son .

Therefore , age of father = 10 + 2 (x+3) ......(ii)

On solving (i) and (ii) we get ,

3x + 7 = 10 + 2(x+ 3)

⇒3x + 7 = 10 + 2x + 6

⇒ x = 16 - 7 = 9.

So,  the present age of son is 9 years and

Father present age is  3 x + 4  = 3 (9) + 4 = 27 + 4 = 31 years .

Final answer:

Hence , the present age of father is 31 years .

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