Plove that (cotA -tan A)÷(cotA+tanA)=cos2A
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Answered by
10
Answer:
Your answer is in the attachment and I also have written the answer below...
Step-by-step explanation:
LHS=SinAcosA(sinA/cosA+cosA/sinA)
SinAcosA(sin2A+cos2A/sinAcosA)
Sin2A+cos2A
1
RHS=1
Therefore,LHS=RHS.
Hopefully this helps you...
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Answered by
0
this is your answer
(cotA-tanA)÷(cotA+tanB)=cos2A
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