Math, asked by Namyasaini, 2 months ago

plrase give answer i will mark brainlent​

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Answers

Answered by sangeethakannan78
0

Step-by-step explanation:

1. -35+(10+-5)=(-35+10)+-5

-35+5 = -45+-5

-40 = - 40

2. -35×(10+-5) = (-35×10)+(-35×-5)

-35×5 = -350 + 175

-175 = - 525

1. is equal

2.is not equal

Hope it helps

mark as brainlist

Answered by SachinGupta01
4

Given :

 \sf \: a \:  =  \: -  \:35

 \sf \: b  \: = \:  10

 \sf \: c \:  = \:  - \: 5

We have to Verify that :

 \sf \: (1) \:  \:  a \:  +  \: ( \: b \: + \: c)  \: =  \: ( \: a \: + \: b \: )  \: + \: c

 \sf \: \:  (2) \:  a  \: \times  \: ( \: b \: + \: c \: )  \: =  \: ( \: a \: \times  \: b \: ) \:   +   \: ( \: a \:  \times c)

_______________________________

So, Let's Start :

 \sf \: (1) \:  \:  a \:  +  \: ( \: b \: + \: c)  \: =  \: ( \: a \: + \: b \: )  \: + \: c

 \sf \: \:  \:   - \: 35 \:  +  \: ( \: 10 \: + \:  - \: 5)  \: =  \: ( \:  -  \:35 \: + \: 10 \: )  \: + \:  -  \:5

 \sf \: \:  \:   -  \:35 \:  +  \: ( \: 10 \:  -   \:5)  \: =  \: ( \:  -  \:35 \: + \: 10 \: )  \:  -  \:5

 \sf \: \:  \:   -  \:35 \:  +  \:   5  \: =  \:  -  \:25  \:  -  \:5

 \sf \: \:   -  \:30  \: =  \:   -  \:30

\sf \: Hence  \: Verified \:...

_______________________________

 \sf \: \:  (2) \:  a  \: \times  \: ( \: b \: + \: c \: )  \: =  \: ( \: a \: \times  \: b \: ) \:   +   \: ( \: a \:  \times c)

 \sf \: \:    -  \:35  \: \times  \: ( \: 10\: + \:  - \:  5\: )  \: =  \: ( \:  -  \:35 \: \times  \: 10 \: ) \:   +   \: ( \:  - 35 \:  \times  - \:  5)

 \sf \: \:    - 35  \: \times  \: ( \: 10\:  - \:  5\: )  \: =  \: ( \:  -  \:350 \:  ) \:   +   \: (  175)

 \sf \: \:    - \:  35  \: \times  \: 5  \: =  \: \:  -  \: 350 \:   \:   +   \:  175

 \sf \: \:    - \:  175  \: =  \: \:  -  \: 175

\sf \: Hence  \: Verified \:...

_______________________________

Some more information :

\boxed{\begin{array} {c|c} \sf{ +,- } & \sf{ - } \\ \dfrac{\qquad\qquad}{} & \dfrac{\qquad}{} \\ \sf{-  ,  +} & \sf{ - } \\ \dfrac{\qquad\qquad}{} & \dfrac{\qquad}{} \\ \sf{+,+} & \sf{ + } \\ \dfrac{\qquad\qquad}{} & \dfrac{\qquad  }{} \\ \sf{-,-} & \sf{ + }\end{array}}

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