Question

PLS 4th QUESTION NEED FAST

Answer 1

Given:AOB is a straight line = 180 degree

(2x+10)+(2x-30)=180

4x-20=180

4x=180+20

4x=200

x=200/4

x=50

angle BOC =(2x-30)

2x50-30

100-30

=70 degree

Answer 2

Given:

∠ AOC = 2x+10°

∠ BOC = 2X - 30°

To find:

m∠ BOC

Solution:

∠AOC + ∠BOC = 180° ↔ ( Linear pair)

2x +30 + 2x -10 = 180°

4x + 20 = 180°

4x = 180 - 20

x = 160 / 4

x = 40

∴ ∠AOC = 2x + 30 = 2 * 40 +30 = 110°

∴∠BOC = 2x - 10 = 2* 40 - 10 = 70°