Question

pls an this q pls pls pls i will mark u as the brainliest ans

Answer 1

Your answer is ---

n(A) = 10
n(B) = 7

A and B both have 5 identical elements

So, n(A-B) = 0

and

n(AUB) = 5


Therefore ,

n(A-B)+n(AUB) = 0+5 = 5

Answer 2

Given that : A and B sets have exactly 5 Identical Elements.

⇒ The Sets A and B have exactly have 5 Elements in Common.

⇒ n(A ∩ B) = 5

We know that n(A - B) = n(A) - n(A ∩ B)

Given that n(A) = 10 and We noticed that n(A ∩ B) = 5

⇒ n(A - B) = 10 - 5 = 5

We know that n(A ∪ B) = n(A) + n(B) - n(A ∩ B)

Given n(B) = 7

⇒ n(A ∪ B) = 10 + 7 - 5

⇒ n(A ∪ B) = 17 - 5 = 12

The Question is Find the value of n(A - B) + n(A ∪ B)

⇒ n(A - B) + n(A ∪ B) = 5 + 12 = 17