Math, asked by sadiyamulla58, 10 months ago

Pls and the question

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Answered by IamIronMan0
0

Answer:

9 \sec {}^{2} (x)  - 9 \tan {}^{2} (x) \\  = 9( \sec {}^{2} (x)  -  \tan {}^{2} (x)) \\  = 9(1) \\  = 9

Answered by shalinik02
0

ANSWER : 9

Step-by-step explanation:

we know

sec^2A - tan^2A = 1

9(sec^2 - tan^2A) = 9×1

= 9

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