Question

pls ans. 29th qs .....hurry!!!

Answer 1

Answer:

Step-by-step explanation:

let 'o' and 'r' be the centre and radius of circle

as Δ abc is an equilateral trangl

= <bca =60'

= <oce=30'

in Δ oec

ce=2cm [radius given]

=   cos 30'=ce/oc

=  √3/2 = 2/oc

oc=4/√3

so radius of lrge circle =2+oc

          =2+4√3           =4.309ap

now area of shaded region = pi r2 - 3pi r2

                                                    [ar of lager circle - ar of 3 smaller circles]

 

= pi[{2+4√3}2 -3*{2}2]

=pi [16√3-8/3]cm2

u can more simplify it

u can also get the radius by joing a with d.{mid point on bc]

by using pgt .u will get the answer 2√3

now draw a point between the line ad

centriod always cut the circle into two ratios =2:1

oa=2/3 *ad  =2/3*2√3     =4/√3

oa+2 = radius ,

4/√3+2  =4.309

thnx

may b hlpful fr u