Question

pls ans 67 . question

Answer 1

LHS----- =cot²A(secA-1)/1+sinA , =cot²A(secA-1)(1-sinA)/((1+sinA)(1-sinA... , =cot²A(secA-1)(1-sinA)/(cos²A) , =(secA-1)(1-sinA)/(sin²A) , =(secA-1)(secA+1)(1-sinA)/(sin²A)(secA+... , =(sec²A-1)(1-sinA)/(sin²A)(secA+1) , =(tan²A)(1-sinA)/(sin²A)(secA+1) , =((sin²A)/(cos²A)(1-sinA))/(sin²A)(secA... , =(1-sinA)/((secA+1)(cos²A)) , =sec²A(1-sinA)/(1+secA)=RHS ....

Answer 2

Ans is in attachment