pls ans as quickly as possible
Answers
Answer
y=8+5x-5
Step-by-step explanation:
Total distance covered = x km
Total taxi fare = Rs. y
Fare for the first kilometer =Rs. 8
Fare for subsequent distance =Rs. 5 per km
Remaining distance = (x -1) km Fare for next (x -1) km = Rs. 5 x (x -1)
Total taxi fare = Rs. 8 + Rs. 5(x -1)
According to the question,
⇒ y = 8 + 5 (x-1)
⇒ y = 8 + 5x – 5
⇒ 5x – y + 3 = 0
Which is the required linear equation.
It can also be written as y = 5x + 3
When x = 0, then y = 5 (0) + 3 ⇒ y = 3
When x = -1, then y= 5 (-1) + 3 ⇒ y=-2
When x = – 2, then y = 5 (-2) + 3 ⇒ y = – 7
You can draw the graph yourself...
Now, plotting the points (0, 3), (-1, -2) and (-2 -7) on a graph paper and joining them, we get a straight line PQ.
Thus, PQ is the required graph of the linear equation y = 5x + 3
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