Math, asked by yoooooo95, 9 months ago

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Answers

Answered by manaswi78
2

Answer:

hope it helps.........

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Answered by BrainlyTornado
3

QUESTION:

Find the value of x.

 \sf  \dfrac{2x -1 3}{5}  -  \dfrac{x -  3}{11}  =  \dfrac{x - 9}{5}  + 1

ANSWER:

  • The value of x = 14.

GIVEN:

 \sf  \dfrac{2x -1 3}{5}  -  \dfrac{x -  3}{11}  =  \dfrac{x - 9}{5}  + 1

TO FIND:

  • The value of x.

EXPLANATION:

 \sf  \dfrac{2x -1 3}{5}  -  \dfrac{x -  3}{11}  =  \dfrac{x - 9}{5}  + 1

 \sf  \dfrac{22x -143}{55}  -  \dfrac{5x -  15}{55}  =  \dfrac{x - 9}{5}  + 1

 \sf  \dfrac{22x -143 - 5x +  15}{55}  =  \dfrac{x - 9}{5}  + 1

 \sf  \dfrac{22x -143 - 5x +  15}{55}  =  \dfrac{x - 9}{5}  +  \dfrac{5}{5}

 \sf  \dfrac{17x -128}{55}  =  \dfrac{x - 9 + 5}{5}

 \sf  \dfrac{17x -128}{11}  =x-4

 \sf  17x -128=  11x - 44

 \sf  6x = 128 - 44

 \sf  6x = 84

 \sf x = 14

HENCE THE VALUE OF x = 14.

VERIFICATION:

 \sf  \dfrac{2x -1 3}{5}  -  \dfrac{x -  3}{11}  =  \dfrac{x - 9}{5}  + 1

Substitute x = 14.

 \sf  \dfrac{2(14) -1 3}{5}  -  \dfrac{14-  3}{11}  =  \dfrac{14 - 9}{5}  + 1

 \sf  \dfrac{28 -1 3}{5}  -  \dfrac{11}{11}  =  \dfrac{5}{5}  + 1

 \sf  \dfrac{15}{5}  -  1 =  1+1

 \sf  3 -  1 =  1+1

 \sf  2 =  2

HENCE VERIFIED.

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