Question

pls ans below question. I don't know how to do it

Answer 1

for solution refer attachment

Answer 2

Hey mate :

Given :

$y = \sqrt{ {x}^{2} + {a}^{2} } \\ diff \: with \: respect \: to \: x \\ \frac{dy}{dx} = \frac{d}{dx} \sqrt{ {x}^{2} + {a}^{2} } .\\ \frac{dy}{dx} = \frac{1}{2 \sqrt{ {x}^{2} + {a}^{2} } } .(2x + 0) .\\ \frac{dy}{dx} = \frac{2x}{ 2\sqrt{ {x}^{2} + {a}^{2} } } . \\ \frac{dy}{dx} = \frac{x}{ \sqrt{ {x}^{2} + {a}^{2} } } . \\ \\ proved.$

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