Question

pls ans fast it's urgent​

Answer 1

Answer:

Explanation:

The given rectangle has a length that is 10 units longer than its width. This can be expressed in the following equation, where l is the length and w is the width of the rectangle.

l=w+10

Since the area of the rectangle is equal to its length multiplied by its width (A=l∗w), and the area of the rectangle is given, the following equation must be true.

75=l∗w

Replacing l in this equation with its value stated in the first equation results in the following.

75=(w+10)∗w

Distribute the variable into the parentheses.

75=w2+10w

w2+10w−75=0

Factor the polynomial.

(w−5)(w+15)=0

5 and −15 are both solutions for this equation, but −15 is not valid as a width for a rectangle. The width of the rectangle is 5 units, which is the shorter side since the length is 10 units longer (l=w+10).

Answer 2

The given rectangle is length that is 10 unit longer that it's width . Thias can be expressed by following equation where I is the length and w is the width of the rectangle .

I = w + 10

Since the area of the rectangle is equal to its length multiplied by it's width ( A = I× w ) , and the area of the rectangle is given , the following must be true .

75 = I × w

Replacing I in this equation with its value stated in the first equation result in the following..

75 = ( w + 10 ) × w

Distribute the varaible into the parentheses .

72 = w2 + 10w

w2 + 10w - 75 = 0

Factor the polynomial .

( w - 5 ) ( w +15 ) = 0

5 and - 15 are both solution for this equation , but -15 is not valid as a width for a rectangle . The width of the rectangle is 5 units , which is the shortrer side since the length is 10 units longer ....

( I = w + 10 )............