PLS ANS FAST linear equations
Attachments:
Answers
Answered by
1
not sure but your question is wrong
Attachments:
Answered by
1
according to question,
k²-k+6=0
k²+2k-3k+6=0
(k²+2k)-(3k+6)
k(k+2)-3(k+2)
(k+2)(k-3)=0
k²-k+6=0
k²+2k-3k+6=0
(k²+2k)-(3k+6)
k(k+2)-3(k+2)
(k+2)(k-3)=0
kartik085:
wait
(k+2)(k-3)=0.
only k
k-1=0
k=1
see the other person who answered
his answer is also 1
and this is quadratic equations
pls mark as brainleist
ur wrong i think
Similar questions