PLS ANS FAST
LOOK BELOW!!
Attachments:
Answers
Answered by
2
In triangle ABE,
<ABE + <AEB + <BAE = 180°
=> 30° + <AEB + 70° = 180°
=> <AEB + 100 = 180
=> <AEB = 80°
Now,
<DEC = <AEB ( Vertically opposite angles)
=> <DEC = 80°
Now,
In triangle DEC,
<DEC + <ECD + <CDE = 180°
=> 80 + 90 + <CDE = 180°
=> 170 +<CDE = 180
=> <CDE = 10°
<ABE + <AEB + <BAE = 180°
=> 30° + <AEB + 70° = 180°
=> <AEB + 100 = 180
=> <AEB = 80°
Now,
<DEC = <AEB ( Vertically opposite angles)
=> <DEC = 80°
Now,
In triangle DEC,
<DEC + <ECD + <CDE = 180°
=> 80 + 90 + <CDE = 180°
=> 170 +<CDE = 180
=> <CDE = 10°
SridharN:
is it right???
Yes
oh wait
its u!!
thank you bro
i believe ur answers are correct
thz again
Answered by
2
In triangle ABE
angle ABE+angleBEA+angleEAB=180
30+BEA+70=180
BEA=180-100
BEA=80
BEA=DEC (vertical opposite)
In triangle ECD
angleECD+angleCDE+angleDEC=180
90+80+CDE=180
CDE=180-170
CDE=10
I hope it will help u
angle ABE+angleBEA+angleEAB=180
30+BEA+70=180
BEA=180-100
BEA=80
BEA=DEC (vertical opposite)
In triangle ECD
angleECD+angleCDE+angleDEC=180
90+80+CDE=180
CDE=180-170
CDE=10
I hope it will help u
Similar questions