Question

pls ans fast pls i beg u guys pls ans​

Answer 1

Answer:

A=l*b

A=30*25

A=750m

750*10

7500 rupees

Step-by-step explanation:

Answer 2

$\: \huge \mathfrak \red{answer}$

$\sf \large{given : length = 30m \: breth \: = 25m \: external \: path \: = 2m}$

$\sf{now \: in \: order \: to \: find \:side\: of \: inner \: squre \: }$

$\sf \: length \: of \: inner \: squre \: 30 - 4 = 26m \\ \\ \sf \: breth \: of \: inner \: squre \: 25 - 4 = 21m$

$\bold {we \: substract \:4 \: coz \: 2m \: is \: taken \: both \: up \: and \: down }$

$\sf to \: find \: aera \: of \: 2m \: stripe \\ \sf\boxed{area \: of \:outer \: squre - inner \: squre \: aera}$

$\sf \: now \: aera \: of \: outer \: rectangle \: = \boxed{length \: \times breth} \\ \\ so \: aera \: of \: outer \: rectangle \: = 30 \times 25 = 750 {m}^{2}$

$\sf aera \: of \: inner \: rectangle \: = \boxed{length \times breth}$

$so \: aera \: of \:inner \: rectangle = 21 \times 26 = 546 {m}^{2}$

$\sf \: therefore \: aera \: of \: 2m \: wide \: section \: = 750 - 546 = 204 {m}^{2}$

$\sf \: then \: pavement \: cost = \boxed{aera \: of \: 2m \:path \: \times cost \: money }$

$pavement \: cost \: = 204 \times 10 = 2040 \: ruppee$

hope it helps you

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