Math, asked by saumya7778, 3 months ago

Pls ans fast



Pls super fast

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Answered by Anonymous
2

 \huge \underline{  \underline{  \star \sf{answer}}}

{\sf{p(x) = 4x {}^{2}  - 12x + 9}} \\ \sf{x = - 2 }  \\  \sf{p( - 2) = 4( - 2) {}^{2} - 12( - 2) + 9 } \\  \sf{p( - 2) = 4(4)  + 24 + 9 } \\  \sf{p( - 2) = 16 + 24 + 9} \\    \boxed{\sf{p( - 2) = 49}}

\sf{p(x) = 4x {}^{2}  - 12x + 9} \\  \sf{x = - 3 } \\  \sf{p( - 3) = 4( - 3) {}^{2} - 12( - 3) + (9)  } \\  \sf{p( - 3) = 4(9) + 36 + 9} \\  \sf{p( - 3) = 36 + 36 + 9} \\   \boxed{\sf{p( - 3) = 81}}

Answered by theju23
0

If x = -2

p(-2) = 4(-2)²-12(-2)+9

= 16+24+9

= 49

If x = -3

p(-3) = 4(-3)²-12(-3)+9

= 36+36+9

= 81

Hope it helps!!

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