Pls ans guyzzz
plz plz plz plz
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0
Step-by-step explanation:
something is missing here,
(y -x) in place (x +y) you take ,
x = (27)⅓ and y = (28)⅓
(y-x) - 1/(x² +xy +y²)
{(y - x)(x²+xy+y²) -1 }/(x²+xy+y²)
use formula,
(a-b)(a²+ab+b²) = a³ -b³
now,
{ y³ - x³ -1}/(x² +xy +y²)
(28 -27 -1)/(x²+xy+y²)
= 0
khyati4267:
thanq
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