Question

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Answer 1

AnSwEr :-

Option d) is the the correct answer to your question.

Reffer to the attachment :)

Answer 2

Step-by-step explanation:

Given:

$\rightarrowtail \bold{\theta = 30^0}$

To find:

$\rightarrowtail \bold{\dfrac{1-sin\theta}{1+sin\theta} }$

Solution:

• ∵ sinФ = sin30°
• ∵ sin30° = 1/2

$\mapsto \bold{\dfrac{1-\dfrac{1}{2} }{1+\dfrac{1}{2} } }$

$\mapsto \bold{\dfrac{\dfrac{1(2)-1(1)}{2} }{\dfrac{1(2)+1(1)}{2} } }$

$\mapsto \bold{\dfrac{\dfrac{1}{2} }{\dfrac{3}{2} } }$

• Remember √ is still there.

$\mapsto \bold{\dfrac{1}{2}\times\dfrac{2}{3} }$

$\mapsto \bold{\sqrt{\dfrac{1}{3} } }$

$\mapsto \bold{\dfrac{\sqrt{1} }{\sqrt{3} } }$

$\hookrightarrow \bold{\dfrac{1}{\sqrt{3} } }$

• (d) 1/√3 is the value of the expression given.