Question

..pls ans it
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Answer 1

Answer:

x = 5, y = 1

Step-by-step explanation:

Given :

First equation : 7(y + 3) - 2(x + 2) = 14

On further solving, we get

→ 7(y) + 7(3) - 2(x) - 2(2) = 14

→ 7y + 21 - 2x - 4 = 14

→ 7y - 2x + 17 = 14

→ 7y - 2x = 14 - 17

→ 7y - 2x = - 3

→ 2x - 7y = 3 ...(i)

Second equation : 4(y - 2) + 3(x - 3) = 2

On further solving, we get

→ 4(y) + 4(- 2) + 3(x) + 3(- 3) = 2

→ 4y - 8 + 3x - 9 = 2

→ 3x + 4y - 17 = 2

→ 3x + 4y = 2 + 17

→ 3x + 4y = 19 ...(ii)

Now,

Multiplying (i) with 3 and (ii) with 2, we get

First equation : 3(2x - 7y) = 3(3)

On further solving, we get

→ 6x - 21y = 9 ...(iii)

Second equation : 2(3x + 4y) = 2(19)

On further solving, we get

→ 6x + 8y = 38 ...(iv)

Subtracting (iii) and (iv), we get

→ (6x - 21y) - (6x + 8y) = 9 - 38

→ 6x - 21y - 6x - 8y = 9 - 38

→ - 29y = - 29

→ y = - 29/- 29

→ y = 1

Putting this value in (i), we get

→ 2x - 7(1) = 3

→ 2x - 7 = 3

→ 2x = 3 + 7

→ 2x = 10

→ x = 10/2

→ x = 5