Question

...pls ans it fast............​

Answer 1

Let AO = H

CD = OB = 60m

A'B = AB = 60 + H

In Δ AOD,

tan30°=Ao\OD=H/OD

OD =√3H

Tan60°=OA/OD

√3=60+60+H/√3H

⇒ 120 + H = 3H

⇒ 2 H = 120

⇒ H = 60 m

Thus, height of the cloud above the lake = AB + A'B = 60 + 60 = 120 m.

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